484m^2-1=0

Solution for 484m^2-1=0 equation:

484m^2-1=0

a = 484; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·484·(-1)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-44}{2*484}=\frac{-44}{968}
=-1/22
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+44}{2*484}=\frac{44}{968}
=1/22
$